Question

Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the
reaction, CaCO3 (s) + 2 HCl (aq) → CaCl2 (aq) + CO2(g) + H2O(l)
What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

Answer 1

Answer:

1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g

∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 g

From the given chemical equation,

CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)

2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3 i.e. 100g

∴ 0.6844 g HCl reacts completely with CaCO3 = 100/73 × 0.6844 g = 0.938 g

PLEASE MARK AS BRAINLIEST.........

Answer 2

Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the

reaction, CaCO3 (s) + 2 HCl (aq) → CaCl2 (aq) + CO2(g) + H2O(l)