Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below: CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l) What mass of CaCl2 will be formed when 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3 ? Name the limiting reagent. Calculate the number of moles of CaCl2 formed in the reaction.
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limiting reagent of the reaction is 2HCl
40+71=111 - CaCl2
40+71=111 - CaCl2
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