Calcium carbonate reacts with aqueous HCL to give CaCl2 and CO2 according to the reaction CaCo3 +2HCL = CaCL2 +CO2+ H2O . a) how many gram of CaCl2 will be produced if 50g of CaCo3 is used?
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Answered by
1
Answer:
22gram
Explanation:
moles of caco3=mass given/molar mass
=50/100=1/2
now,if 1 moles of caco3 gives 1 moles of Cacl2 .therefore 1/2 moles of caco3 gives 1/2 moles of Cacl2.
Cacl2 obtain will be}=1/2= mass given/ molar mass
1/2=mass/111
mass of Cacl2 obtain will be=55.5 gram
Answered by
0
Answer:
Here's Your answer CaCO3+2HCl→CaCl2+CO
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