Calcium carbonate reacts with aqueous hcl to give cacl2 and co2 .What mass of caco3 is required to react completely with 25 ml of 0.75 M HCl?
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Answer:
CaCO3 + 2 HCl = CaCl2 -+CO2+ H2O
1 mole of caco3 reacts with 2 mole of. HCl
Moles given in que HCl =0.75x25 =MV Milli moles =18.75
18.75 x10^-3 moles. HCl reacted with =18.75x10^-3/2 =9.375 x10^-3 moles of caco3
Mass of CaCO3 =mole X molecular mass
9.375x 10^-3x100=0.9375 gm
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