Calcium carbonate reacts with hcl to give cacl2 and co2 and h2o what mass of 20%impure caco3 required to react completely with 250 ml of 0.50 M hcl
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Answer:
Eq. of CaCO
3
= Eq. of HCl.
Eq. of HCl =
1000
25×0.75
Eq. of CaCO
3
=
100
2×mass
Mass of CaCO
3
=0.9375g
Explanation:
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