Chemistry, asked by JassChahal3400, 11 months ago

Calclculat the mass of potassium chlorate required to liberate 6.72 dm3 of oxygen at stp .molar mass of kclo3 is 122.5 gm/mol

Answers

Answered by vyaswanth

0

Explanation:

do (122.5×6.72)÷22.4=36.75g

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