Question

calcualate the compound interest on rupees 1600 for 1½ uears at 10% annum when the interest os compounded half yearly​

Answer 1

Answer:

I dont know

Step-by-step explanation:

2+2=5

varun dhawan

Shikhar dhawan

Answer 2

Answer:

252.20

Step-by-step explanation:

$A = P(1 + \frac{r}{n})^(nt)$

where,

A = final amount

P = principal amount

r = rate of interest

n = number of times interest applied per time period

t = number of time period elapsed

From the given data,

P = 1600, t = 1$1/2$ = 3/2, r = 10 and n = 3

Substituting these values in the above equation we get,

⇒  A = 1600(1 + 10/3)^(9/2)

⇒ A = 1852.20

Interest = Final amount - Principal amount

             = 1852.20 - 1600

             = 252.20