Calcualte the molal depression constant of a solvent, which has freezing point 16.6 °C and latent heat of fusion
180.75 Jg–1
Answers
Answered by
4
Answer:
Given,
T
f
=273+16.6=289.6K
L
f
=180.75J/g
R=8.314J/K/mol
K
f
=?
∴K
f
=
1000×L
f
RT
f
2
=
1000×180.75
8.314×(289.6)
2
∴K
f
=3.86.
Explanation:
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Answered by
0
Answer:
3.86 is the correct answer
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