Physics, asked by sjayaprakashchowdary, 8 months ago

Calcualte the ratio of the strength of electric repulsion between electrons is larger
than the gravitational attraction between them?

Answers

Answered by samiraza12

4

Answer: Thus the Coulomb force is F = 8.19 × 10−8 N. This is also an attractive force, although it is traditionally shown as positive since gravitational force is always attractive. The ratio of the magnitude of the electrostatic force to gravitational force in this case is, thus, FFG=2.27×1039 F F G = 2.27 × 10 39 .

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