calcuate the number of atoms presents in 90g of H2O
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Answer:
For water we have 2 hydrogen atoms and one oxygen, so the atomic weight of water is 1+1+16=18, so a mole of water is 18 grams. We have 90g of water so we have 90/18 = 5 moles of water.
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Answer:
the atomicity of a molecule of H2O = 2(1u) +1(16u) = 18u
We have 90g of water so we have 90/18 = 5 molecules of water
so,
5 x 18 = 90u
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