Question

calcuius - calpeyron equation?​

Answer 1

Explanation:

On a pressure–temperature (P–T) diagram, the line separating the two phases is known as the coexistence curve. The Clausius–Clapeyron relation gives the slope of the tangents to this curve. Mathematically,

{\displaystyle {\frac {\mathrm {d} P}{\mathrm {d} T}}={\frac {L}{T\,\Delta v}}={\frac {\Delta s}{\Delta v}},} {\frac {\mathrm {d} P}{\mathrm {d} T}}={\frac {L}{T\,\Delta v}}={\frac {\Delta s}{\Delta v}},

where {\displaystyle \mathrm {d} P/\mathrm {d} T} \mathrm {d} P/\mathrm {d} T is the slope of the tangent to the coexistence curve at any point, {\displaystyle L} L is the specific latent heat, {\displaystyle T} T is the temperature, {\displaystyle \Delta v} \Delta v is the specific volume change of the phase transition, and {\displaystyle \Delta s} \Delta s is the specific entropy change of the phase transition.