calculat the amount of hcl using 0.05 sodium corbonate solution
Answers
Answer:
calculat the amount of hcl using 0.05 sodium corbonate solution
Answer:
The mass of HCl present is 1.825 grams
Explanation:
To calculate the number of moles for given molarity, we use the equation:
\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}Molarity of the solution=
Volume of solution (in L)
Moles of solute
Molarity of sodium carbonate solution = 0.05 M
Volume of solution = 500 mL = 0.500 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
\begin{gathered}0.05M=\frac{\text{Moles of sodium carbonate}}{0.500L}\\\\\text{Moles of sodium carbonate}=(0.05mol/L\times 0.500L)=0.025mol\end{gathered}
0.05M=
0.500L
Moles of sodium carbonate
Moles of sodium carbonate=(0.05mol/L×0.500L)=0.025mol
The chemical equation for the reaction of sodium carbonate and HCl follows:
Na_2CO_3+2HCl\rightarrow 2NaCl+CO_2+H_2ONa
2
CO
3
+2HCl→2NaCl+CO
2
+H
2
O
By Stoichiometry of the reaction:
1 mole of sodium carbonate reacts with 2 moles of HCl
So, 0.025 moles of sodium carbonate will react with = \frac{2}{1}\times 0.025=0.05mol
1
2
×0.025=0.05mol of HCl
To calculate the mass of HCl for given number of moles, we use the equation:
\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}Number of moles=
Molar mass
Given mass
Molar mass of HCl = 36.5 g/mol
Moles of HCl = 0.05 moles
Putting values in above equation, we get:
\begin{gathered}0.05mol=\frac{\text{Mass of HCl}}{36.5g/mol}\\\\\text{Mass of HCl}=(0.05mol\times 36.5g/mol)=1.825g\end{gathered}
0.05mol=
36.5g/mol
Mass of HCl
Mass of HCl=(0.05mol×36.5g/mol)=1.825g