calculat the malicular mass of the C2H5OH
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Answer:
molecular mass of ethanol is 46.07g/mol
Explanation:
1 mol of C is 12.01g,1 mol of H is 1.01g,1 mol of O is 16.00g then the molecular mass of ethanol (C2H5OH) is 2×12.01+6×1.01+1×16.00= 46.07g/mol
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46.07 g/mol
Formula: C2H5OH
Melting point: -114.1 °C
Density: 789 kg/m³
thank you (*_*)
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