Calculat volume of O2 at STP required for complete combustion of 2.64L of acetylene at STP. 2C2H2 + 5O2 = 4CO2 + 2H2O
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no. Of moles of C2H2=2.64/22.4
=0.1
We know,
no. Of moles of acetylene÷ stoichiometry of acetylene=no. Of moles of O2(n)÷ stoichiometry of O2
0.1/2=n/5
n=(5*0.1)/2
=0.25
Volume of 02 required for combustion= 0.25*22.4
= 5.6l
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