Question

Calculate :- 1+2+3+4-5-6+7×1÷4=?​

Answer 1

Answer:

This question can be solved by BODMAS rule.

Step-by-step explanation:

1+2+3+4-5-6+7×1÷4

=10-11+7/4

=7/4-1

=3/4

Answer

Answer 2

Given: The equation is$1+2+3+4-5-6+7\times1\div4$.

We have to solve the above equation.

• By using the Bodmas rule, we are solving the above equation.
• As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$1+2+3+4-5-6+7\times1\div4$

$= 1+2+3+4-5-6+7\times1/4\\= 1+2+3+4-5-6+7/4\\= 1+2+3+4-5-6+1.75\\= 3+3+4-5-6+1.75\\= 6+4-5-6+1.75\\= 10-5-6+1.75\\= 5-6+1.75\\= -1+1.75\\= 0.75$

Hence, the solution of the above equation is$0.75$.