Question

calculate (1) effective resistance (2) current and (3) potential difference across 10 ohm resistor of a circuit shown in fig​

Answer 1

Answer:

Explanation:

1: R=R1+R2

effective resistance =5ohm+10ohm

=15ohm

2: current= V/R

=2/15

=0.13A

3: potential difference across 10 ohm resistor = IR

= 0.13•10V

=1.3V

Answer 2

Explanation:

1. ER=R1×R2=(5+10)ohm=15ohm
2. I=V/R=2/15A=0.13A
3. V=IR=(2/15A)×10ohm=4/3v=1.33v

hope you will able to understand the answer....