Math, asked by yukta8991, 6 months ago

Calculate
(1) The compound interest for the second year on rupees 15000 invested for 3years at 8% per annum (2) the sum due at the end of third year.

Answers

Answered by BrainlyUnnie
1

Simple Interest I=  \frac{PTR}{100}

Here for first year,

P=Rs 15,000

N=1 year

R=6 %

So, Interest at the end of 1st year I= \frac{15,000*1*6}{100}  

                                                        =Rs900

And for second year,

P= Rs15,000 + Rs900 = Rs15,900

N=1year

R=6 %

I=  \frac{15900*1*6}{100}

=Rs954

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