calculate
3.5 & 7resistors are connected is parallel to a 6 v battery
a) Total resistance of the circuit
b) Electric current flows through the circuit
c) Electric current flows through each resistor
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as shown in abouve circuit diagram
R total will be-
by the Ohm's law
V=IR
so I =V/R
I=6/7+3.5
I total = 8.71A
so current on each will be
I1=V/R
I1=6/3.5
I1=1.71A
I2=6/7
I2=0.85A
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