Math, asked by aradhanamohapatra48, 10 months ago

calculate 5+(-5)+5(-5)............191 times ​

Answers

Answered by ohnoomg87
2

Answer:

5

Step-by-step explanation:

  5 + (-5) + 5 + (-5) ... + 5 + (-5) + 5

= [5 + (-5)] × 95 + 5

= 0 × 95 + 5

= 5

Hope it's helpful.

Answered by Sarwaswa
0

 5 + (– 5) + 5 + (– 5) + 5 ......

=  (5 – 5) + (5 – 5) + 5........

=   0 + 0 + 0 + 0 + 5......

=   5

Number of 5 in [5 + (– 5) + 5 + (– 5) + 5] is five.

AND five is an odd number.

and it's soluction is 5.

  5 + (– 5) + 5 + (– 5) + 5 + (- 5) ......

=  (5 – 5) + (5 – 5) + (5 – 5).......

=  0    

Number of 5 in [5 + (– 5) + 5 + (– 5) + 5 + (- 5)] is Six.

AND six is even number.

and it's soluction is 0.

We observed that, when number of five is odd answer = 5

and when it is even answer = 0

question ) 191

191 is an odd number then, answer = 5    

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