Question

calculate (997)3 by using algebraic identities​

Answer 1

Answer:

(1000-3)^3=1000^3-3^3-3*1000*3(997)

=100,00,00,000-27-9000(997)

Step-by-step explanation:

is it is cube..if yes

here is your answer.

(a-b)^3=a^3-b^3-3ab(a-b) is an identity to use here..