Question

Calculate
A
Principal = 50,000 and rate = 8%. Find the amount to be paid after 10 years.
B.Amount = 32,400, principal = 24,000 and time = 10 years Find the rate of interest.
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Answer 1

The compound interest on Rs. 50,000 at 4% per annum for two years compounded anually is :

Answer

C.I. = Amount - Principle

=> P((1+100r​)T​−1)

CI = 50,000(1+1004​)2​−1)

C.I.= 4080.

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Answer 2

Answer:

a]It is given that  

Principal (P) = 50000

Rate of interest (r) = 8% p.a. = 4% semi-annually

Period (n)= 1  

2

1

​  

 years = 3 semi-annually

We know that  

Amount = P(1+r/100)  

n

 

Substituting the values  

= 50000(1+4/100)  

3

 

By further calculation  

= 50000(26/25)  

3

 

= 50000×26/25×26/25×26/25

= 56243.20

Here

Compound interest = A - P

Substituting the values  

= 56243.20−50000

= 6243.20

Step-by-step explanation:

b]P=24000Rs

n=3 because due to semi-annually 3×  

2

1

​  

 months are there

r=10% but for  

2

1

​  

 years r=  

2

10

​  

=5%.

=24000(1+0.05)  

3

 

=24000×1.05×1.05×1.05

Amount =27783

CI=27783−24000

CI=3783.