Question

calculate a resultant of two forces 3N and 4N which is inclined at an angle 60° between them.​

Answer 1

Answer:

Resultant force is √40 N.

Explanation:

Given:-

Force, F1 = 3 N

Force, F2 = 4 N

Angle, ∅ = 60°

Now, we know that the resultant of two forces inclined at some angle is given by the formula:-

F = √ F1² + F2² + F1 × F2 × Cos ∅

Putting the given values, we get:-

F = √ 3² + 4² + 3 × 4 × cos 60°

F = √ 9 + 25 + 12 × ½

F = √ 40 N

Hence, the resultant force is √40 N.

Hope it helps :-))