calculate a resultant of two forces 3N and 4N which is inclined at an angle 60° between them.
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Answer:
Resultant force is √40 N.
Explanation:
Given:-
Force, F1 = 3 N
Force, F2 = 4 N
Angle, ∅ = 60°
Now, we know that the resultant of two forces inclined at some angle is given by the formula:-
F = √ F1² + F2² + F1 × F2 × Cos ∅
Putting the given values, we get:-
F = √ 3² + 4² + 3 × 4 × cos 60°
F = √ 9 + 25 + 12 × ½
F = √ 40 N
Hence, the resultant force is √40 N.
Hope it helps :-))
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