calculate a) total displacement b) acceleration of the part ab,bc,cd
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Answer:
s=0.5×(30+15)×50
s=45*25m
s= 1125m
Acceleration at AB=5ms-²
BC=0ms-²
CD=-10MS-²
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Explanation:
(a) total displacement = 30 m
(b) acceleration of the part ab =1/2 × 10 × 50
= 250
- acceleration of the part bc = 15 × 50 = 750
- acceleration of the part cd = 1/2 × 5 × 50 = 125
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