calculate % abudance of Ag_109 if it is known that silver only exist in two istopes Ag_107 and Ag_109. Given average atomic weight of Ag=108.5
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Answer:
This must be a combination of these two isotopes. So the % of the other isotope must be 48.16%.
To work with these percentages in an equation I'll use them as decimals.
So now I can start putting them into an equation:
107.87
=
(
106.905
⋅
0.5184
)
+
(
x
⋅
0.4816
)
Because both of the isotope masses, multiplied by their percentage, would give us the overall average mass.
107.87
=
55.419552
⋅
(
x
⋅
0.4816
)
Worked out the brackets that we can work out, and then rearrange to give:
107.87
−
55.419552
=
(
x
⋅
0.4816
)
Again rearrange:
52.450448
=
(
x
⋅
0.4816
)
And final rearranging:
x = 52.450448
-----------------
0.4816
x = 108.909
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