Calculate acoustic impedance of air and water at STP using the data 3313m kg 10,ms 332,m kg 29.1---=r=n=rwaterairairand .ms 15001-=nwater Derive the formula used.
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Derivation of the formulas:
(Specific) Acoustic impedance z of sound wave in a fluid medium is the resistance the particles of the medium offer to the propagation of sound wave. Impedance is inversely proportional to the wave number k = ω/v, where ω = angular frequency and v = velocity of the wave.
The more the density ρ and stiffness K in the medium are, the more the speed v of propagation of sound.
z defined as √(K*ρ) = √(B * ρ)
K = stiffness constant = Modulus of elasticity
B = Bulk modulus for fluids = K
ρ = density of the medium.
For fluids (air and water) B = - P / (ΔV/V) = stress / volume strain
B = excess pressure / volume strain
We know that sound waves are the result of SHM of the particles of the medium. Using this principle, the sound modeled as a longitudinal excess pressure P wave along with longitudinal displacements s of particles, we derive that :
P = B s₀ k cos (ω t - k x) for s = s₀ sin(ωt - k x)
Then using the excess pressure model, we find the excess force ΔF on an element of volume A Δx of the medium, by Pressure P times area A. That will be ΔF = A * ΔP = - B s₀ k² sin (ω t - k x) Δx
We get the acceleration by dividing by mass Δm = A ρ Δx . We know for given expression for s, acceleration is d²s/dt². Comparing both expressions we get that:
v = √(B / ρ) or , B = v² ρ
Substituting this in the definition of z, we get:
Acoustic Impedance z = √(v² ρ²) = v ρ
============
at STP, we have
Density of air = 1.29 kg/m³ speed of sound in air = 332 m/s
Density of water = 1,000 kg/m³ Speed of sound in water = 1500 m/s
Refractive index of air = 1 refractive index of water = 1.33
So acoustic impedance of air = z = 1.29 * 332
= 428.28 kg/m²-s or 428.28 Rayl or Ry
z of water = 1500 * 1000
= 1.5 * 10⁶ kg/m²-s or Ry
==================
Another derivation for acoustic impedance.
Acoustic impedance z = Acoustic pressure p / acoustic fluid velocity u
s (x,t) = s₀ Sin(ω t - k x) -- displacement of particles
u (x,t) = particle speed = ds/dt = s₀ ω Cos (ωt - k x)
p(x,t) = - K ds/dx = - B s₀ k Cos (ωt - k x)
v(t) = speed of the wave at any x.
Thus z = B k/ω = B / v = ρ v as B = ρ v² for sound.
(Specific) Acoustic impedance z of sound wave in a fluid medium is the resistance the particles of the medium offer to the propagation of sound wave. Impedance is inversely proportional to the wave number k = ω/v, where ω = angular frequency and v = velocity of the wave.
The more the density ρ and stiffness K in the medium are, the more the speed v of propagation of sound.
z defined as √(K*ρ) = √(B * ρ)
K = stiffness constant = Modulus of elasticity
B = Bulk modulus for fluids = K
ρ = density of the medium.
For fluids (air and water) B = - P / (ΔV/V) = stress / volume strain
B = excess pressure / volume strain
We know that sound waves are the result of SHM of the particles of the medium. Using this principle, the sound modeled as a longitudinal excess pressure P wave along with longitudinal displacements s of particles, we derive that :
P = B s₀ k cos (ω t - k x) for s = s₀ sin(ωt - k x)
Then using the excess pressure model, we find the excess force ΔF on an element of volume A Δx of the medium, by Pressure P times area A. That will be ΔF = A * ΔP = - B s₀ k² sin (ω t - k x) Δx
We get the acceleration by dividing by mass Δm = A ρ Δx . We know for given expression for s, acceleration is d²s/dt². Comparing both expressions we get that:
v = √(B / ρ) or , B = v² ρ
Substituting this in the definition of z, we get:
Acoustic Impedance z = √(v² ρ²) = v ρ
============
at STP, we have
Density of air = 1.29 kg/m³ speed of sound in air = 332 m/s
Density of water = 1,000 kg/m³ Speed of sound in water = 1500 m/s
Refractive index of air = 1 refractive index of water = 1.33
So acoustic impedance of air = z = 1.29 * 332
= 428.28 kg/m²-s or 428.28 Rayl or Ry
z of water = 1500 * 1000
= 1.5 * 10⁶ kg/m²-s or Ry
==================
Another derivation for acoustic impedance.
Acoustic impedance z = Acoustic pressure p / acoustic fluid velocity u
s (x,t) = s₀ Sin(ω t - k x) -- displacement of particles
u (x,t) = particle speed = ds/dt = s₀ ω Cos (ωt - k x)
p(x,t) = - K ds/dx = - B s₀ k Cos (ωt - k x)
v(t) = speed of the wave at any x.
Thus z = B k/ω = B / v = ρ v as B = ρ v² for sound.
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