Calculate active mass of 10gram CaCO3
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Answer:
active mass of CaCo3 is mole pesent in 1
Explanation:
active mass-the concentration of a reacting substance expressed usually in moles per liter
In a reaction molar concentration of the reactant is called its active mass.
Therefore active mass of CaCo3 is mole pesent in 1 lt
mole in 10 gm of CaCo3 =weight/mol.weight =10/100 =.1 mole
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Answer:
ca.40g. c.12g o3. 48g. 40+12+48=100 so active mass of caco3 is 100g
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