Question

Calculate active mass of 10gram CaCO3

Answer 1

Answer:

active mass of CaCo3 is mole pesent in 1

Explanation:

active mass-the concentration of a reacting substance expressed usually in moles per liter

In a reaction molar concentration of the reactant is called its active mass.

Therefore active mass of CaCo3 is mole pesent in 1 lt

mole in 10 gm of CaCo3 =weight/mol.weight =10/100 =.1 mole

Answer 2

Answer:

ca.40g. c.12g o3. 48g. 40+12+48=100 so active mass of caco3 is 100g