Question

Calculate AH° for the reaction
2C1F (g) + O2(g) - CIO(g) + OF, (9)
from the following data:
(1) F.(g) + CIF(g) → CIF (1)
AH = - 139.2 kJ
(ii) 2C1F (1) + 20 (9) CLO(g) + 30F,(g) AH = +533.4 kJ
(iii) F (g) + 10 (8) OF (9)
AH° = 24.7 kJ​

Answer 1

Answer:

ANSWER

O2(g)+O2(g)→O3  ΔH=−107.2KJ/mol

To calculate average bond enthalpy in O3 

The equation of the bond enthalpy is 

the change in enthalpy of reaction =(the sum of the bonding energy of reactants)-(the sum of the bonding energy of the products)

The change of enthalpy is given as =− 107.2KJ/mol

-107.2KJ/mol =(bond enthalpy sum of reactants)-2(bond enthalpy sum of products)

-107.2KJ/mol = 498.7KJ/mol-2(bond enthalpy of products)

498.7KJ/mol is the BE of O2 

its 2 times the bonding enthalpy products because of their 2 kinds of bonds in O3- a single and a double bond

605.9KJ/mol = 2BE

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