Question

Calculate amount and compound interest on ₹18,000 for 2 years at 10℅ p.a compound annually.​

Answer 1

Answer:

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Answer 2

Solution :

$\underline{\bf{Given\::}}}$

• Principal, (P) = Rs.18000
• Rate, (R) = 10% p.a.
• Time, (n) = 2 years

$\underline{\bf{Explanation\::}}}$

Using formula of the compounded annually;

$\boxed{\bf{Amount=Principal\bigg(1+\frac{R}{100} \bigg)^{n}}}}$

A/q

$\longrightarrow\sf{A=18000\bigg(1+\cancel{\dfrac{10}{100} }\bigg)^{2}}\\\\\\\longrightarrow\sf{A=18000\bigg(1+\dfrac{1}{10} \bigg)^{2}}\\\\\\\longrightarrow\sf{A=18000\bigg(\dfrac{10 + 1}{10} \bigg)^{2}}\\\\\\\longrightarrow\sf{A=18000\bigg(\dfrac{11}{10} \bigg)^{2}}\\\\\\\longrightarrow\sf{A=180\cancel{00} \times \dfrac{11}{\cancel{10}} \times \dfrac{11}{\cancel{10}} }\\\\\\\longrightarrow\sf{A=Rs.(180\times 11\times 11)}\\\\\longrightarrow\bf{A=Rs.21780}$

Now, as we know that compound Interest;

$\longrightarrow\sf{C.I.=Amount-Principal}\\\\\longrightarrow\sf{C.I. = Rs.21780 - Rs.18000}\\\\\longrightarrow\bf{C.I. = Rs.3780}$

Thus;

The amount & compound Interest will be Rs.21780 & Rs.3780 .