Question

Calculate amount of aluminum required to get 1120kg of iron which aluminum reacts with ferricoxide

Answer 1

Explanation:

Here it is clear that , 2 moles of Aluminium produces 2 moles of iron metal.

so, no of moles of Aluminium = no of moles of iron

or, weight of Aluminium/atomic weight of Al = weight of iron/atomic weight of iron

or, weight of aluminium/27 = 1120/56

or, weight of aluminium = 1120 × 27/56 = 540 grams.

hence, 540g of aluminium required getting 1120g of iron by given reaction

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