Question

Calculate amount of Cu deposited at cathode when passage of 3 amp. Current through CuSO4 solution for 80 min. [Molar mass of Cu = 63.5 g.mol1 ]​

Answer 1

Answer:

From faraday's law of electrolysis, we get

W=Zit= E

it

Where, W= Deposited amount

E= Equivalent weight

F=Faraday

i=Electricity passed

t= Time

⇒1.27=

96500

63.5

×2×t

⇒t=965 sec