Question

Calculate amount of heat required to raise the temperature of 5 grams of iron from 25 degree centigrade to 75 degree centigrade the specific heat capacity of iron is 0.450 Joule per gram

Answer 1

Answer: 112.5 Joules

Explanation:

$Q= m\times c\times \Delta T$

Q= heat gained

m= mass of the substance = 5g

c = heat capacity of  iron= 0.450 J/g ° C      

$\Delta T={\text{Change in temperature}}=(75-25)^oC=50^oC$  

$Q=5g\times 0.450J/g^oC\times50^oC$

Q= 112.5 Joules

Thus heat gained by 5 g of iron is = 112.5 Joules

Answer 2

Answer : The amount of heat required is, 112.5 J

Solution :

Formula used :

$Q= m\times c\times \Delta T$

where,

Q = heat required

m = mass of the iron = 5 g

c = heat capacity of iron = $0.450J/g^oC$      

$\Delta T=\text{Change in temperature}=(75-25)=50^oC$  

Now put all the given values in the above formula, we get the amount of heat required.

$Q=5g\times 0.450J/g^oC\times50^oC$

$Q=112.5J$

Therefore, the amount of heat required is, 112.5 J