Calculate amount of heat required to rise the temperature of 100g of water is 10°to15°c
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Answer:
9kcal
Explanation:
m=100g,C=1calg
−1
o
C
−1
ΔT=(95−5)
o
C=90
o
C
Q=mCΔT
=100g×1calg
−1
o
C
−1
×90
o
C
=100×1×90cal
=9000cal=9kcal.
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