Chemistry, asked by kumariswati9309, 12 hours ago

Calculate amount of NaCl required to prepare 250 cm cube of 0.2 m molarity solution

Answers

Answered by ManasiTripathi

0

Answer:

0.05 mol

Explanation:

v= 250cm3

= 250*10^(-3)dm3

=1/4 dm3

number of mole = 0.2*1/4mol

= 0.05 mol

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