Question

calculate amount of Naoh required to make solution of 200 ml from which 50ml solution further diluted to 400 ml and then mixed to 0.5M, 200ml solution to make 0.4M solution ​

Answer 1

Answer:

0.57 this is not answer you do like that.

Explanation:

Number of moles of NaOH in 10 mL of 2 M solution =

1000 mL/L

10 mL

×2 mol/L=0.02 mol

Number of moles of NaOH in 200 mL of 0.5 M solution =

1000 mL/L

200 mL

×0.5 mol/L=0.1 mol

Total number of moles of NaOH=0.02+0.1=0.12 mol

Total volume =10+200=210 mL=

1000 mL/L

210 mL

=0.210 L

Final concentration =

0.210 L

0.12 mol

=0.57 M