Question

calculate and compare the energies of two radiations ,one with a wavelength 300nm and other with 600nm

Answer 1

Answer:

ANSWER

E

1

=hc/λ

1

,E

2

=hc/λ

2

E

2

E

1

=

λ

1

hc

×

hc

λ

2

E

2

E

1

=

λ

1

λ

2

=

800

400

2E

1

=E

2

option C

Explanation:

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