Question

calculate and compare the energies of two radiations ,one with a wavelength 400nm and other with 800nm

Answer 1

Calculation:

E = hν

h = Planck’s constant = 6.626 x 10(-34) J s

ν = frequency

λ = Wavelength = 400 nm

C = Speed of light = 3 x 10(8) m/s

ν = C / λ

Substitute in the equation,

E = 6.626 x 10(-34) J s x 3 x 10(8) m/s / 400 x 10(-9) m

E = 5 x 10(-19) J

When λ = Wavelength = 800 nm

E = 6.626 x 10(-34) J s x 3 x 10(8) m/s / 800 x 10(-9) m

E = 2.5 x 10(-19) J

Comparison:

Since wavelength is inversely proportional to energy, the radiation with 400 nm has higher energy than the radiation with 800 nm.

Answer 2

Answer:

This is the answer of your question

#MARK AS BRAINLIST