Math, asked by aravvarshney80pcbme9, 4 months ago

calculate angle ABC and BAD in the following :-
THOSE WHO GIVE FAST AND RIGHT ANSWER I MARK THE ANSWER BRAINLIST ANSWER....AND VOTE THE ANSWER..​

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Answers

Answered by nightread
6

Answer:

AD, CD, AB and BC are equal as given in the figure. Hence ΔADC and ΔABC are isosceles triangles.

∠DAC = ∠ACD = x

x + x + 64° = 180° (Angle Sum Property)

2x + 64° = 180°

2x = 180° - 64°

2x = 116°

x = 116°/2

x = 58°

∠BAC = ∠DAC = ∠ACD = ∠BCA = 58° as given in the figure.

∠BAC + ∠DAC = ∠BAD

58° + 58° = 116°

∠ABC = x

∠ABC + ∠BAC + ∠BCA = 180° (Angle Sum Property)

x + 58° + 58° = 180°

x + 116° = 180°

x = 180° - 116°

x = 64°

ANS = ∠BAD is 116° , ∠ABC is  64°

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