calculate angle ABC and BAD in the following :-
THOSE WHO GIVE FAST AND RIGHT ANSWER I MARK THE ANSWER BRAINLIST ANSWER....AND VOTE THE ANSWER..
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AD, CD, AB and BC are equal as given in the figure. Hence ΔADC and ΔABC are isosceles triangles.
∠DAC = ∠ACD = x
x + x + 64° = 180° (Angle Sum Property)
2x + 64° = 180°
2x = 180° - 64°
2x = 116°
x = 116°/2
x = 58°
∠BAC = ∠DAC = ∠ACD = ∠BCA = 58° as given in the figure.
∠BAC + ∠DAC = ∠BAD
58° + 58° = 116°
∠ABC = x
∠ABC + ∠BAC + ∠BCA = 180° (Angle Sum Property)
x + 58° + 58° = 180°
x + 116° = 180°
x = 180° - 116°
x = 64°
ANS = ∠BAD is 116° , ∠ABC is 64°
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