Question

calculate angle of deviation of angle of incidence of 35 40 45 50 55 degree in prism for class 10

Answer 1

Hey mate ...

here's ur answer

 The incident light ray in, is bent by........
 an angle θ1 = i−r1
θ2 = e−r2D = θ1+θ2 
= i + e (r1+r2)

To go further with the calculation we need to add up the corners to 180 degree as it is a triangle a prism.  

A +(90−r1)+(90−r2) = 180

D = i+e−A 

Hope it helps❤

Answer 2

Answer:

The angle of deviation for angle of incidence 35°, 40°, 45°, 50°, and 55° are 10.99°, 12.87°, 14.91°, 17.09°, and 19.49° respectively.

Snell's Law:

Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the refractive index of the material.

(sin i / sin r) = μ, where i is the incidence angle, r is the refraction angle, and μ is the refractive index.

Angle of deviation:

The angle of deviation is the difference between the angle of incidence and the angle of refraction of a ray of light when traveling from one medium to another.

Angle of deviation (δ) = angle of incidence (i) - angle of refraction (r)

Explanation:

Let us take the refractive index of the prism as 1.41

For angle of incidence 35°:

i = 35°, μ = 1.41

Using Snell's law, we get

$\frac{sin 35}{sin (r)} = 1.41$

$\frac{0.574}{sin(r)} = 1.41$

$sin(r) = \frac{0.574}{1.41}$

$sin (r) =0.4071$

$r = sin^{-1}(0.4071)$

r = 24.01°

Angle of deviation δ = 35 - 24.01

Angle of deviation δ = 10.99°

For angle of incidence 40°:

i = 40°, μ = 1.41

Using Snell's law, we get

$\frac{sin 40}{sin (r)} = 1.41$

$\frac{0.643}{sin(r)} = 1.41$

$sin(r) = \frac{0.643}{1.41}$

$sin (r) =0.4560$

$r = sin^{-1}(0.4560)$

r = 27.13°

Angle of deviation δ = 40 - 27.13

Angle of deviation δ = 12.87°

For angle of incidence 45°:

i = 45°, μ = 1.41

Using Snell's law, we get

$\frac{sin 45}{sin (r)} = 1.41$

$\frac{0.707}{sin(r)} = 1.41$

$sin(r) = \frac{0.707}{1.41}$

$sin (r) =0.5014$

$r = sin^{-1}(0.5014)$

r = 30.09°

Angle of deviation δ = 45 - 30.09

Angle of deviation δ = 14.91°

For angle of incidence 50°:

i = 50°, μ = 1.41

Using Snell's law, we get

$\frac{sin 50}{sin (r)} = 1.41$

$\frac{0.766}{sin(r)} = 1.41$

$sin(r) = \frac{0.766}{1.41}$

$sin (r) =0.5433$

$r = sin^{-1}(0.5433)$

r = 32.91°

Angle of deviation δ = 50 - 32.91

Angle of deviation δ = 17.09°

For angle of incidence 55°:

i = 55°, μ = 1.41

Using Snell's law, we get

$\frac{sin 55}{sin (r)} = 1.41$

$\frac{0.819}{sin(r)} = 1.41$

$sin(r) = \frac{0.819}{1.41}$

$sin (r) =0.5809$

$r = sin^{-1}(0.5809)$

r = 35.51°

Angle of deviation δ = 55 - 35.51

Angle of deviation δ = 19.49°

Therefore, the angles of deviation are 10.99°, 12.87°, 14.91°, 17.09°, and 19.49°.

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