calculate angle of emergence if the angle of incidence is 43 degrees and the angle of deviation is 41 degrees
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Explanation:
In case of an equilateral prism
angle of prism+ angle of deviation =angle of incidence +angle of emergence.
60+41 =43+x
x=101-43 =58 degrees.
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The angle of emergence is 58°
Explanation:
Given as :
For A Prism
The angle of incidence = ∠i = 43°
The angle of deviation = ∠d = 41°
The angle of prism = ∠p = 60°
Let The angle of emergence = ∠e
According to question
From figure
Angle of prism + Angle of deviation = angle of incident + angle of emergence
i.e ∠p + ∠d = ∠i + ∠e
Or, 60° + 41° = 43° + ∠e
Or, 101° = 43° + ∠e
∴ ∠e = 101° - 43°
i.e ∠e = 58°
So, The angle of emergence = ∠e = 58°
Hence, The angle of emergence is 58° Answer
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