Question

Calculate angleAOC , angle BOD and angle AOE in the adjoining fig.angle COD=90, angle BOE =72and AOB is a straight line

Answer 1

Answer:

90 +72=180

162=180

180-162

=018answer

Answer 2

Appropriate Question:

• Calculate ∠AOC , ∠BOD and ∠AOE in the adjoining fig.angle ∠COD=90, ∠BOE =72⁰ and AOB is a straight line.

Given:

• ∠COD=90⁰
• BOE =72⁰
• AOB is a straight line

To find:

• ∠AOC
• ∠ BOD
• ∠ AOE

Solution:

• Since, AOB is a straight line the sum of all angles on the lower side of AOB at the point O on it, is 180°.

∴ ∠AOB + ∠BOE = 180°

$\longmapsto$3x + 72° = 180°

$\longmapsto$ 3x = (180° – 72°)

$\longmapsto$ 3x = 108°

$\longmapsto$x = 108/3

$\longmapsto$ x = 36°

Again, AOB is a straight line and O is a point on it.

So, the sum of all angles on the upper side of AOB at a point O on it,is 180°.

∴ ∠AOC + ∠COD + ∠DOB = 180°

$\longmapsto$ x + 90 + y = 180 [∵ ∠AOC = x°, ∠COD = 90° and ∠DOB = y°]

$\longmapsto$ 36 + 90 + y = 180 [∵ x = 36°]

$\longmapsto$ 126° + y° = 180°

$\longmapsto$ y = 180 – 126

$\longmapsto$ y = 54°

∴ ∠AOC = x° = 36°, ∠BOD = y° = 54°

∠AOC = 3x = (36 × 3) = 108°

Thank you!

@itzshivani