calculate angular speed of hour hand
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Answer:
Is this answer still relevant and up to date? The minute takes one hour = 60 s/min × 60 min = 3600 s to go around, so ω = 2π / 3600 rad.s-1 = 1.7 × 10-3 rad.s-1. The hour hand takes 12 hours = 12 hours × 60 min/hour × 60 s/min = 43200 s to do 2π radians, so ω = 2π rad/43200 s = 1.5 × 10-4 rad.s-1.
Explanation:
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The angular velocity is independent of the clock size, however for larger clocks the linear velocity of the pointers at the end of the hands will be greater.
The second hand goes through 2π radians in 1 min, or 2π radian/60 seconds,
so ω = π/30 rad.s-1 = 0.03 rad.s-1.
The minute takes one hour = 60 s/min × 60 min = 3600 s to go around,
so ω = 2π / 3600 rad.s-1 = 1.7 × 10-3 rad.s-1.
The hour hand takes 12 hours = 12 hours × 60 min/hour × 60 s/min = 43200 s to do 2π radians,
so ω = 2π rad/43200 s = 1.5 × 10-4 rad.s-1.
Hope helps
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