Math, asked by kgourvai, 10 days ago

calculate approximate value of 5√245 by using Lmvt​

Answers

Answered by VELINENI
5

Answer:

78.26 is the answer

Step-by-step explanation:

this is the answer for the question

Answered by preety89
3

Lagrange's Mean value theorem states that

f'(x_0)=\frac{f(x_0+\Delta x)-f(x_0)}{\Delta x}

Given,

f(x)=\sqrt[5]{x} \\x_0=243\\\Delta x=2

Now,

f'(x)=\frac{x^{-\frac{4}{5} }}{5}

f(243+2)=f'(243)\times 2 +f(243)\\\sqrt[5]{245}=\frac{1}{405} \times 2 + 3\\\sqrt[5]{245} =0.0049+3\\\sqrt[5]{245}=3.0049

Hence 5√245 is 3.0049 using Lmvt.

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