Question

Calculate at what distance from the origin, the graph of the equation X/2+у/3=1 intersects
the x axis and the y axis.​

Answer 1

$Given \: equation \: \frac{x}{2} + \frac{y}{3} = 1$

$It \: is \: of \:the \: form \: \frac{x}{a} + \frac{y}{b}=1$

$\blue{ ( Two \: intercepts \: form ) }$

$Where , x \: intercept = a \: and$

$y \: intercept = b$

$Here, x \: intercept (a) = 2 , \: and$

$y \: intercept ( b ) = 3$

$\therefore The \: straight \:line \: intersects$

$x \:axis \: at \: A(2,0) \: Y\: axis \:at \: B(0,3)$

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