Question

calculate athe electric current density of uniform wire connected to a battery of emf 3.5V and negligible internal resistance.The resistance of the wire is 2.0 ohm and its area of coss section is 0.70 x10^-6 m^2​

Answer 1

hlo mate here is ur ans.

given,

EMF of battery = 3.5 v

Resistance of the wire = 2.0 ohms

Area of cross section = 0.70*10^-6m^2

Current,I = V/R ==>3.5/2 ==>1.75

Current density = J = I/A = 1.75/0.70*10^-6m^2

i.e...........            J = 2.5*10^6.

hope thishelps uh dear ;)

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