Question

calculate atomic mass of propin​

Answer 1

$\\ \sf\longmapsto Atomic \:mass\:of\:Propin=C_3H_6$

$\\ \sf\longmapsto 3(12u)+6(1u)$

$\\ \sf\longmapsto 36u+6u$

$\\ \sf\longmapsto 42u$

Answer 2

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$Atomic \: composition \: of \: Propin \: \longrightarrow C _{3}H _{6} \\ \\ \implies mass \: of \: propin \: \longrightarrow C \times 3 + H \times 6 \\ \\ \implies mass \: of \: propin \: \longrightarrow 12 \times 3 + 1\times 6 \\ \\ \implies mass \: of \: propin \: \longrightarrow 36 + 6 \\ \\ \implies mass \: of \: propin \: \longrightarrow 42u$