Question

calculate avg kinetic energy of a gas molecule at 27 degree celcius.

Answer 1

average kinetic energy of gas molecule is given by 3/2.RT.

3/2R300=450R

R=universal gas constant value

Answer 2

Given that,

Temperature, T = 27 degree Celsius

To find,

The average kinetic energy of a gas molecule

Solution,

The average kinetic energy of a gas molecule at temperature T is given by :

$K=\dfrac{3}{2}kT$

k is Boltzmann constant

Put T = 27°C or 300 K

$K=\dfrac{3}{2}\times 1.38\times 10^{-23}\times 300\\\\K=6.21\times 10^{-21}\ J$

So, the avg kinetic energy of a gas molecule at 27 degree Celsius is $6.21\times 10^{-21}\ J$.

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Calculate avg kinetic energy of a gas molecule at 27 degree celcius.

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