Question

calculate boiling point of .2m urea .Know for water is .52K kgmol_1​

Answer 1

dT = i*Kf*m

i = vont haff factor for urea = 1

Kf = 0.52 K/molal

m = 0.2 molal

dT = 0.52*0.2 = 0.104 K

dT = T2 - T1 = 0.104K

T2 = 373+0.104 = 373.104K

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