Calculate change in internal energy of 3 mol of helium whne it's temprature is increased by 2 K
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energy formulae : 3/2nRT
Internal energy = 3/2(3)(8.31(2)
Internal energy = 74.8 J
:-)
energy formulae : 3/2nRT
Internal energy = 3/2(3)(8.31(2)
Internal energy = 74.8 J
:-)
Riishika:
what the fuk ??
Answered by
5
Hey Buddy,^_^
Solution-:
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