Question

calculate charge in faraday in 2 moles of Mg 2+VE​

Answer 1

Answer:

hope it helps you

mark me a brainliest

Explanation:

No of moles of Mg^+2 ion = given wt/molar wt

here,

given wt = 48 g

molar wt = 24 g/mol

no of moles of Mg^+2 ion = 48/24

= 2 mol

we can see that in one mole of Mg+2 ion , 2 mole electrons occur

so, in two moles of Mg^+2 ions = 2×2 moles of electrons occur .

now, no of electrons = no of mole of electrons× Avogadro's constant

= 4 × 6.023 × 10²³

we also know,

charge of one electron = 1.6× 10^-19 C

so, charge by total electrons = 4 × 6.023 × 10²³ × 1.6 × 10^-19 C

= 38.54 × 10⁴ C

= 3.854 × 10^5 C