Calculate charge in faraday in the following
i ) 1Mole of Na+ ions
(ii).2 mole of Mg+2 ions..
i) 1.5 mole of al+3 ions
4 0.3 mole of so4-2ions
۱/
Answers
Answered by
7
Answer:
Given:
(a) 1 mole of Na⁺ ion
(b) 0.2 mole of Mg²⁺ ion
(c) 0.3 mole of SO₄²⁻ ion
To Find:
Charge in faraday in the given cases.
Calculation:
- We know that 1 Faraday = charge carried by 1 mole electric charge carriers.
(a) 1 mole of Na⁺ ions = 1 mole of positive charge.
⇒ Positive charge carried by 1 mole of Na⁺ ions = 1 faraday
(b) 0.2 mole of Mg²⁺ ions = (0.2 × 2) = 0.4 moles of positive charge
⇒ Positive charge carried by 0.2 mole of Mg²⁺ ions = 0.4 faraday
(c) 0.3 mole of SO₄²⁻ ions = (0.3 × 2) = 0.6 moles of negative charge
⇒ Negative charge carried by 0.3 mole of SO₄²⁻ ions = 0.6 faraday
Explanation:
plz mark me as brainliest
Similar questions